Which statement about the following equilibrium is correct
250, (g) + O2(g) = 250,(g) AH = -188.3 kJ moll
(a) The value of K falls with a rise in temperature
(b) The value of K, falls with increasing pressure
(c)
Adding V,05 catalyst increase the equilibrium yield of sulphur
trioxide
(d)
The value of K, is equal to K.
Dube
Answers
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Answer:
In the reaction, H
2
(g)+I
2
(g)⇌2HI(g), in a 2 litre flask 0.4 mole of each H
2
and I
2
are taken. At equilibrium 0.5 mol of HI are formed. The value of equilibrium constant K
c
will be 11.1.
0.5 moles of HI will be obtained from 0.25 moles of H
2
and 0.25 moles of I
2
.
0.4−0.25=0.15 moles of H
2
and 0.4−0.25=0.15 moles of I
2
will remain.
The equilibrium constant
K
c
=
[H
2
][I
2
]
[HI]
2
K
c
=
(
2 L
0.15 mol
)×(
2 L
0.15 mol
)
(
2 L
0.5 mol
)
2
K
c
=11.1
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