Math, asked by farnajbegum1859, 1 year ago

Which statement describes the graph of the system of equations below? 1.5x + 0.2y = 2.68 1.6x + 0.3y = 2.98 The lines are parallel. The lines overlap at all points. The lines intersect at (1.6,1.4). The lines intersect at (3.1,0.5).

Answers

Answered by Kristiania
47

Here we are given two equations:

1.5x + 0.2y = 2.68

1.6x + 0.3y = 2.98

Now let us try to graph them so that we can find the answer.

Using table method to graph.

1.5x + 0.2y = 2.68

Let us say x=0,

0+0.2y=2.68

y=13.4

first point is (0,13.4)

let us say y=0,

1.5x +0=2.68

x=1.79

second point is (1.79,0)

So two point for first equation are (0,13.4) and (1.79,0).

Now for second equation,

1.6x+0.3y=2.98

let us say x=0,

0+0.3y = 2.98

y=9.93

first point is (0,9.93)

now say y=0,

1.6x + 0 =2.98

x=1.86

second point is (1.86,0)

two points for second equation are (0.9.93) and (1.86,0)

Graph is shown in figure below.

Answer: So the two lines intersect at point (1.6,1.4).



Attachments:
Answered by pavanadevassy
3

Answer:

line intersect at (1.6 , 1.4)

Step-by-step explanation:

The two equations given are :

1.5x + 0.2y = 2.68

1.6x + 0.3y = 2.98

Solve this two equation :

                     0.3 ( 1.5x + 0.2y = 2.68 )  = 0.45x + 0.06y = 0.804

                     0.2  ( 1.6x + 0.3y = 2.98 ) = 0.32x + 0.06y = 0.596

                0.45x + 0.06y = 0.804

          (-)   0.32x + 0.06y = 0.596

             = 0.13x   + 0        = 0.208

                                0.13x = 0.208

                                      x = 0.208 / 0.13

                                      x =  1.6    

Put the value of x in any of the equation, we will get the value of y

                           1.5x + 0.2y = 2.68

                  (1.5 * 1.6 ) + 0.2y = 2.68

                            2.4 + 0.2y = 2.68

                                     0.2y = 2.68 - 2.4

                                          y = 0.28 / 0.2

                                          y = 1.4

Hence the intersection point is ( 1.6 , 1.4)

#SPJ2

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