Which statement describes the graph of the system of equations below? 1.5x + 0.2y = 2.68 1.6x + 0.3y = 2.98 The lines are parallel. The lines overlap at all points. The lines intersect at (1.6,1.4). The lines intersect at (3.1,0.5).
Answers
Here we are given two equations:
Now let us try to graph them so that we can find the answer.
Using table method to graph.
Let us say x=0,
0+0.2y=2.68
y=13.4
first point is (0,13.4)
let us say y=0,
1.5x +0=2.68
x=1.79
second point is (1.79,0)
So two point for first equation are (0,13.4) and (1.79,0).
Now for second equation,
let us say x=0,
0+0.3y = 2.98
y=9.93
first point is (0,9.93)
now say y=0,
1.6x + 0 =2.98
x=1.86
second point is (1.86,0)
two points for second equation are (0.9.93) and (1.86,0)
Graph is shown in figure below.
Answer: So the two lines intersect at point (1.6,1.4).
Answer:
line intersect at (1.6 , 1.4)
Step-by-step explanation:
The two equations given are :
1.5x + 0.2y = 2.68
1.6x + 0.3y = 2.98
Solve this two equation :
0.3 ( 1.5x + 0.2y = 2.68 ) = 0.45x + 0.06y = 0.804
0.2 ( 1.6x + 0.3y = 2.98 ) = 0.32x + 0.06y = 0.596
0.45x + 0.06y = 0.804
(-) 0.32x + 0.06y = 0.596
= 0.13x + 0 = 0.208
0.13x = 0.208
x = 0.208 / 0.13
x = 1.6
Put the value of x in any of the equation, we will get the value of y
1.5x + 0.2y = 2.68
(1.5 * 1.6 ) + 0.2y = 2.68
2.4 + 0.2y = 2.68
0.2y = 2.68 - 2.4
y = 0.28 / 0.2
y = 1.4
Hence the intersection point is ( 1.6 , 1.4)
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