Question

Which statement is true concerning the vertex and axis of symmetry of h(x)=−2x2+8x?

Answer 1

Answer:

x=2

Step-by-step explanation:

The general vertex form of a quadratic function is this: h(x) = -a(x-h) + k.

The vertex is at (h,k) and the axis of symmetry is at x=h.

h(x)=-2x(x-4)

h(2)=-2×2(2-4)=-4(-2)=8

ans x=2

Answer 2

The axis of symmetry is x=2 and vertex of the parabola is (2,8).

Step-by-step explanation:

If a parabola is defined as

$f(x)=ax^2+bx+c$

then,

Axis of symmetery : $x=-\dfrac{b}{2a}$

$Vertex=(-\dfrac{b}{2a},f(-\dfrac{b}{2a})$

The given function is

$h(x)=-2x^2+8x$

Here, a=-2, b=8,c=0.

Axis of symmetry : $x=-\dfrac{8}{2(-2)}=2$

Hence, the axis of symmetry is x=2.

Substitute x=2 in the given function.

$h(2)=-2(2)^2+8(2)=-8+16=8$

So, vertex of the parabola is (2,8).

#Learn more:

Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function y = 4x2 – 8x – 3.

https://brainly.in/question/5873503