Question

Which statement is true of a rectangle that has an area of 4x2 + 39x – 10 square units and a width of (x + 10) units? The rectangle is a square. The rectangle has a length of (2x – 5) units. The perimeter of the rectangle is (10x + 18) units. The area of the rectangle can be represented by (4x2 + 20x – 2x – 10) square units.

Answer 1

Perimeter of rectangle = 10x + 18 units is only correct option if Area of rectangle  = 4x² + 39x - 10 & width = x + 10

Step-by-step explanation:

Area of rectangle  = 4x² + 39x - 10

= 4x² + 40x - x - 10

= 4x(x + 10) - 1(x + 10)

= (4x - 1)(x + 10)

Area of rectangle  = Length * width

width = x + 10

Length = 4x - 1

 4x - 1 ≠ x + 10  

=>  Length ≠ Width ( hence rectangle is not square)

4x - 1 ≠ 2x – 5  hence   Length ≠ (2x – 5

Perimeter of rectangle = 2(x + 10 + 4x - 1)  = 10x + 18

4x² + 20x – 2x – 10  = 4x² + 18x - 10 ≠ 4x² + 39x - 10

Perimeter of rectangle = 10x + 18 units is only correct option

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Answer 2

Answer:

Its C on edge

Step-by-step explanation:

I just did it