Which statement is true of a rectangle that has an area of 4x2 + 39x – 10 square units and a width of (x + 10) units? The rectangle is a square. The rectangle has a length of (2x – 5) units. The perimeter of the rectangle is (10x + 18) units. The area of the rectangle can be represented by (4x2 + 20x – 2x – 10) square units.
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Perimeter of rectangle = 10x + 18 units is only correct option if Area of rectangle = 4x² + 39x - 10 & width = x + 10
Step-by-step explanation:
Area of rectangle = 4x² + 39x - 10
= 4x² + 40x - x - 10
= 4x(x + 10) - 1(x + 10)
= (4x - 1)(x + 10)
Area of rectangle = Length * width
width = x + 10
Length = 4x - 1
4x - 1 ≠ x + 10
=> Length ≠ Width ( hence rectangle is not square)
4x - 1 ≠ 2x – 5 hence Length ≠ (2x – 5
Perimeter of rectangle = 2(x + 10 + 4x - 1) = 10x + 18
4x² + 20x – 2x – 10 = 4x² + 18x - 10 ≠ 4x² + 39x - 10
Perimeter of rectangle = 10x + 18 units is only correct option
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write the polynomial which represents area of rectangle whose ...
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11
Answer:
Its C on edge
Step-by-step explanation:
I just did it
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