Question

Which statement is wrong regarding PC13F, molecule -
it is nonpolar
%s-character is more in equitorial bonds.
its dipole moment is non-zero F-P-C1 bond angle is 90°​

Answer 1

Answer:

HEY MATE

HEY MATE HERE'S YOUR ANSWER

(A) In the combination of s and p orbitals; with increase in p character, the Bond angle decreases.

The above statement is correct based on the following facts:-

There is a relation between the BOND ANGLE and s-character, s-character is a contribution of s-orbital in Hybridization.

S-character is directly proportional to Bond angle i.e.

S-character α Bond Angle

Combination of S & P orbitals gives rise to Hybrid orbitals and more the s-character of a Hybrid molecule has, the greater the angle between their bond.

We can conclude that the statement is correct based on Bent's Rule Equation;-

which states that - cosx=

s−1

s

where x = a Bond angle

s= % s-character in the bond.

It clearly explains that with increase in p character the Bond angle will be minimum/it will decrease and vice versa in case of maximum s-character.

(B) H-C-H Bond angle>H-C-F Bond angle in CH

3

F molecule

This statement is also CORRECT. As mentioned above (Bent's Rule); s-character contributed by the 3 Hydrogen towards Carbon is more than that of Fluorine's contribution.

Hence we observe a Higher Bond angle in H-C-H compared to H-C-F

H-C-H Bond angle=110.3degree

H-C-F Bond angle=108degree.

(C) Since statement (B) is correct; statement (C) is ruled out