Question

Which term if ap:3,15,27,39 will be 132 more then 54th term?

Answer 1

Step-by-step explanation:

hope it helps you.!!

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Here :-

a = 3

$\rightarrow{d=t_{2}-t_{1}}$

= 15 - 3

= 12

★Now we have :-

$\rightarrow{a_{54}=a+53d}$

3 + 53 × 12

= 3 + 636

= 639

$\fbox{Assume an 132 more than its 54th term}$

$\rightarrow{a_{n}=a_{54}+132}$

= 639 + 132

= 771

a + (n - 1)d = 771

$\fbox{Substitute the values we get :-}$

3 + (n - 1) × 12 = 771

12(n - 1) = 771 - 3

12(n - 1) = 768

${\boxed{\sf\:{(n-1)=\dfrac{768}{12}}}}$

n = 64 + 1

n = 65

${\boxed{\sf\:{Therefore\;we\;get}}}$

$\fbox{65th term is 132 more than it's 54th term}$