Question

which term is 0 of AP 14,12,10​

Answer 1

Answer:

Heres your answer

Given

a= 14 , d= 12-14= -2

Zero term =?

We know that

$an = a + (n - 1)d \\ \\ 0 = 14 + (n - 1) - 2 \\ \\ 0 = 14 - 2n + 2 \\ \\ 0 = 16 - 2n \\ \\ - 16 = - 2n \\ \\ \frac{16}{2} = n \\ \\ 8 = n$

8= n

Therefore the answer is 8....

Hope it helps ✌✌.....

Answer 2

Answer:

here is your answer mate .

common difference =12-14= -2

A =14

Last term = 0 ,

then,

Sn= n/2(2a +(n-1)d)

fill the values and get the.answer