Math, asked by 5dhengajdie, 1 year ago

which term is the first positive term in -63 -59 -55

Answers

Answered by Anonymous
7

Heya....

Here's your answer.........


                            HaPpY PrOpOsE DaY



Let, the A.P. is

-63, -59, -55,............

Here,

a = -63

d = -59 - ( -63 )

=> -59 + 63

=> 4

n = ?

an = 0



So, put the values in the following formula:

an = a + ( n - 1 ) d

0 = -63 + ( n - 1 ) 4

63 = ( n - 1) 4

63/4 = n - 1

63/4 + 1 = n

63+4 / 4 = n

67 / 4 = n

16.3 = n


Here, we'll neglect .3 and take it as 17th term of this A.P.





Thanks....!!!

XD

Sorry baby 'wink'


gmehta801: well done
gmehta801: root 3 cot^2 theta - 4 cot theta + root 3 = 0, then find value of cot^2 theta + tan^2 theta
Anonymous: thanks
gmehta801: ans tthis
5dhengajdie: mistake
5dhengajdie: 0 cant be positive
5dhengajdie: hi
Answered by Anonymous
3

\huge\mathfrak{Bonjour\: Mate}

Solution:-

given:-

a (first term) = -63

d( common difference) = -59 - (-63) = 4

find:-

first positive term (n) = ?

Solution:-

we don't know the first positive term..

then we take it as

a(n) = 0

formula for finding AP

a(n) = a + (n - 1) d

put the values of all terms in formulae

0 = -63 + (n - 1)4

0 = -63 + 4n - 4

0 = -67 + 4n

67 = 4n

n = 67/4

n = 16.3

For ease , we can neglect .3 from 16.3

and we get our first positive no.

16

Hope it helps you⚡⚡

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