Question

Which term of A.P. 1,5,9,13.... is 101 ?? ​

Answer 1

Answer:

Step-by-step explanation:

★Hence,the 26,th term of the given AP is 101

Step-by-step explanation:

★Given:

First term = a = 1

Difference = d = 5 - 1 = 4

a(n) = 101

★To find:

n'th term

★Solution:

⇒ aₙ = a + (n-1)d

⇒ 101 = 1 + (n-1)4

⇒101 = 1 + 4n-4

⇒101 = 4n-3

⇒4n = 104

⇒ n = 104/4

⇒ n = 26

★Hence,the 26,th term of the given AP is 101

Answer 2

Answer:

here common difference of AP =4

Step-by-step explanation:

term =a+(n_1)d

101=1+(n_1)4

101_1 whole divided by 4=n_1

100/4=n-1

25+1=n

26=n

101 is the 26th term of this AP

HOPE THIS HELPS