Math, asked by Anonymous, 9 days ago

Which term of A.P. 1,5,9,13.... is 101 ??​

Answers

Answered by AllenGPhilip
3

Answer:

★Hence,the 26,th term of the given AP is 101

Step-by-step explanation:

★Given:

First term = a = 1

Difference = d = 5 - 1 = 4

a(n) = 101

★To find:

n'th term

★Solution:

⇒ aₙ = a + (n-1)d

⇒ 101 = 1 + (n-1)4

⇒101 = 1 + 4n-4

⇒101 = 4n-3

⇒4n = 104

⇒ n = 26

★Hence,the 26,th term of the given AP is 101

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