which term of A.p 15 ,13¾,12½,11½.......... . . .......
is the first negative term
Answers
Answered by
8
a₁ = 15
a₂ = 13³/₄ = 55/4
a₃ = 12¹/₂ = 25/2
a₄ = 11¹/₂ = 23/2
d = a₂ - a₁
= 55/4 - 15
= 55-60/4
= -5/4
0 > 15 + (n-1)-5/4
0 > 15 + 5/4 -5n/4
65/4 > -5n/4
65 > 5n
13 > n
therefore the 12th term of ap is the first negative term.
a₂ = 13³/₄ = 55/4
a₃ = 12¹/₂ = 25/2
a₄ = 11¹/₂ = 23/2
d = a₂ - a₁
= 55/4 - 15
= 55-60/4
= -5/4
0 > 15 + (n-1)-5/4
0 > 15 + 5/4 -5n/4
65/4 > -5n/4
65 > 5n
13 > n
therefore the 12th term of ap is the first negative term.
Anonymous:
thanks bahi
Answered by
7
Answer: 14th term
Explanation:
a=15, d=13¾-15
= -5/4
Let nth term be first -ve term
Tn= a + (n-1)d
= 15 + (n-1) (-5/4)
= 15 + [ (-5/4n) - (-5/4) ]
= 15 -5/4n + 5/4
= 15 + 5/4 -5/4n
= 65/4 - 5/4n. [ 15×4/4 + 5/4 =
60+5/4 = 65/4 ]
65/4 - 5/4n < 0
-5/4n < -65/4
5/4n > 65/4
n > 65/4 × 4/5
n > 65/5
n > 13
Therefore, 14th term is the first -ve term of the give A.P.
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