Question

which term of A.P: 3,8,13,18,........is 108.?​

Answer 1

Step-by-step explanation:

The given sequence is 3, 8, 13, 18, ....108

'a' = 3, 'd' = 5, last term = 108, 'n' = ?

t^n==a+(n−1)d

⟹108=3+(n−1)5

⟹108=3+5n−5

⟹108=5n−2

⟹108+2=5n

⟹110=5n

⟹n=110/5

⟹n=22

The 22th term is 108..

Answer 2

Answer:

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