Which term of A P:3,8,13,18.....is 78?
Answers
Yo!
Here's the answer! :))
Given AP: 3,8,13,18....
To find: which term of this ap is 78. That is, "n".
Solution:
TN=78.
a=3.
d= t2-t1 = 8-3
= 5.
We know,
Tn= a+(n-1)d
Substituting the values we get:
78= 3+(n-1)×5.
78=3+ 5n-5.
78= –2+5n.
78+2= 5n.
80= 5n.
n= 80/5.
Therefore,
n= 16.
Hence the 16th term of this AP is 78.
Hope it helps!
–TGA.
Hello!!!
So, Let when the first term of AP = a
and common difference = d
number of terms =n
and last term= l
Since AP =3,8,13,18...78
a=3
d=(8-3)=5
l = 78
Using the formula l=a+(n-1)d
78=3+(n-1)5
or, 78-3=5n-5
or, 75+5=5n
or, n=80/5
or ,n=16
So, 78 lies in 16th term of given AP.
Hope it helps !!!! :D