which term of A.P.8,11,14,17,....,is 758
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a=8,d=3,l=758
l=a+(n-1)d
758=8+(n-1)3
758-8=(n-1)3
750=(n-1)3
750/3=(n-1)
250=n-1
n=251
l=a+(n-1)d
758=8+(n-1)3
758-8=(n-1)3
750=(n-1)3
750/3=(n-1)
250=n-1
n=251
Prachi12345:
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