Question

Which term of A.P.9,12,15,.......is 132? Solve​

Answer 1

Step-by-step explanation:

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♡ ↪ Hence, 42th term of the AP is 132. ◉ An AP is a sequence of numbers in which the difference between two consecutive number is same.

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Answer 2

Answer:

a1=9

d=a2-a1=12-9=3

x=a+d(n-1).=132

9+3(n-1)=132

3(n-1)=123

n-1=41

n=42.th term..