Question

Which term of a sequence 4,7,10,15..... is 37?​

Answer 1

Answer:

12 th term

Step-by-step explanation:

$a = 4 \\ d = 3 \\ an = 37 \\ an = a + (n - 1)d \\ 37 = 4 +( n - 1)3 \\ 33 = (n - 1)3 \\ 11 = n - 1 \\ n = 12$

Answer 2

The 12th term of an AP is 37.

Step-by-step explanation:

The given AP are:

4, 7, 10, 13, .....

Here, first term (a) = 4, common difference(d) = 7 - 4 = 3 and $a_{n} =37$

Let nth ter is 37.

To find, the value of n = ?

We know that,

The nth term of an AP

$a_{n} =a+(n-1)d$

⇒ 4 + (n - 1)3 = 37

⇒ (n - 1)3 = 37 - 4 = 33

⇒ n - 1 = $\dfrac{33}{3} =11$

⇒ n = 11 + 1 = 12

Thus, the 12th term of an AP is 37.