Which term of a sequence 4,7,10,15,.........is37?
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Answer:
12th term
Step-by-step explanation:
here 1st term = a = 4
common difference = d = 3
let nth term = tn = a+(n-1)d = 37
=> 4+(n-1)×3 = 37
=> 3n-3 = 37-4 = 33
=> 3n = 33+3 = 36
=> n = 36/3 = 12
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