Math, asked by powersantuk5002, 6 months ago

WHICH TERM OF AN A.P. 16,11,6,1,....IS -54?

Answers

Answered by Anonymous
7

\textbf{\underline {\underline {Solution:-}}}

A = 16,

An=-54.

d= 11-16=5

An = A+(n-1)d

-54=16+(n-1)5

-54-16=(n-1)5

70/5=n-1

14=n-1

14+1=n

n=15

\textbf{\underline {The 15th Term Of The A.P Would Be -54.}}

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