Question

Which term of an A.P 2,7,12,17: is 137

Answer 1

a=2
d=5
tn=137

tn=a+(n-1)d
137=2+(n-1)5
137=2+5n-5
137=5n-3
140=5n
n=140/5
n=28


.
. . =137 is 28 th term of this A.P

Answer 2

a=2
d=5
l=137
a+(n-1)d=l
2+(n-1)5=137
(n-1)5=137-2=135
(n-1)=135/5
(n-1)=27
n-1=27
n=28
Hence 28 term of the AP is 137..