Question

which term of an A. P 3/√7, 4/√7, 5/√7,.......is 17/√7​

Answer 1

Answer: 15th terms

d = a2-a1

d = 1/√7

an = a1 + (n-1)d

17/√7 = 3/√7 + (n-1) 1/√7

17/√7 - 3/√7 = (n-1) 1/√7

14/√7 * √7 = n-1

14 = n-1

n =14+1 =15