Math, asked by sam494, 1 year ago

which term of an A.P. 3,8,13,18,.............is 78?

Answers

Answered by Annabeth
91
a=3           d= 8-3 = 5              n=? 
 a_{n} = a+ (n-1)d
⇒78 = 3 + (n-1)5
⇒75 = (n-1)5
⇒n-1 = 15
⇒n = 16

∴78 is the 16th term of the given A.P.
Answered by Anonymous
25

For the following A.P : 3,8,13,18,------, 78 


First term (t1) = a = 3,common difference (d) = 8 - 3 = 5 and last term (tn) = 78 



The general term of A.P is 


tn = a + (n - 1) d 


78 = 3 + (n - 1)5 


78 = 3 + 5n - 5 


78 = - 2 + 5n 


78 + 2 = 5n 


80 = 5n 


80/5 = n 


16 = n 


n= 16 



16th term of A.P : 3,8,13,18,is 78.



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