which term of an A.P. 3,8,13,18,.............is 78?
Answers
Answered by
91
a=3 d= 8-3 = 5 n=?
= a+ (n-1)d
⇒78 = 3 + (n-1)5
⇒75 = (n-1)5
⇒n-1 = 15
⇒n = 16
∴78 is the 16th term of the given A.P.
= a+ (n-1)d
⇒78 = 3 + (n-1)5
⇒75 = (n-1)5
⇒n-1 = 15
⇒n = 16
∴78 is the 16th term of the given A.P.
Answered by
25
For the following A.P : 3,8,13,18,------, 78
First term (t1) = a = 3,common difference (d) = 8 - 3 = 5 and last term (tn) = 78
The general term of A.P is
tn = a + (n - 1) d
78 = 3 + (n - 1)5
78 = 3 + 5n - 5
78 = - 2 + 5n
78 + 2 = 5n
80 = 5n
80/5 = n
16 = n
n= 16
16th term of A.P : 3,8,13,18,is 78.
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