which term of an A.P 3,8,13,18 is 78
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Answered by
2
First term, a = 3 Last term, an = 78 Common difference, d = 5
n = ?
an = a + (n-1)d
=> 78 = 3 + (n-1)5
=> 78 – 3 = (n-1)5
=> 75 = (n-1)5
=> 75/5 = (n - 1)
=> 15 = n – 1
=> n = 15 + 1
=> n = 16
n = ?
an = a + (n-1)d
=> 78 = 3 + (n-1)5
=> 78 – 3 = (n-1)5
=> 75 = (n-1)5
=> 75/5 = (n - 1)
=> 15 = n – 1
=> n = 15 + 1
=> n = 16
Answered by
3
Hey mate..
========
GIVEN ,
AP:-- 3, 8 ,13, 18.......78
Let n th term of an AP be 78
Now,
Here ,
First term, a = 3
Common Difference = (8 - 3) = 5
We know,
a(n) = 78
=> a + ( n - 1 ) d = 78
=> 3 + ( n - 1 ) 5 = 78
=> 3 + 5n - 5 = 78
=> 5n - 2 = 78
=> 5n = 80
=> n = 80/5
Thus ,
n = 16
Therefore,
In 16th term , we will get 78
#racks..
========
GIVEN ,
AP:-- 3, 8 ,13, 18.......78
Let n th term of an AP be 78
Now,
Here ,
First term, a = 3
Common Difference = (8 - 3) = 5
We know,
a(n) = 78
=> a + ( n - 1 ) d = 78
=> 3 + ( n - 1 ) 5 = 78
=> 3 + 5n - 5 = 78
=> 5n - 2 = 78
=> 5n = 80
=> n = 80/5
Thus ,
n = 16
Therefore,
In 16th term , we will get 78
#racks..
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