which term of an A.p 3,8,13,18........is 78
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Answered by
5
In the given A.P :
a = 3
d = 8-3 = 5
an = 78
n = ?
an = a +(n-1)d
78 = 3 +(n-1)5
75/5 = n-1
n = 16
78 is the 16th term.
hope this helped you .......!
a = 3
d = 8-3 = 5
an = 78
n = ?
an = a +(n-1)d
78 = 3 +(n-1)5
75/5 = n-1
n = 16
78 is the 16th term.
hope this helped you .......!
moinu:
if the sum of the first p terms of an A.P is equal to the sum of the q term.Then show that sum of it's first p+q term is zero.
Answered by
1
For the following A.P : 3,8,13,18,------, 78
First term (t1) = a = 3,common difference (d) = 8 - 3 = 5 and last term (tn) = 78
The general term of A.P is
tn = a + (n - 1) d
78 = 3 + (n - 1)5
78 = 3 + 5n - 5
78 = - 2 + 5n
78 + 2 = 5n
80 = 5n
80/5 = n
16 = n
n= 16
16th term of A.P : 3,8,13,18,is 78.
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