Question

which term of an A.P.7,11,15....is 139....

Answer 1

ANSWER IS.......
given series is 7,11,15.......139
here a=7
n=n
d=11-7→=4
an=a+(n-1)d
139=7+(n-1)4
139=7+4n-4
139=3+4n
136=4n
34=n
it is 34th term in series
I HOPE THIS WILL HELP U.....

Answer 2

Hey There

$a_n = 139\\a = 7\\d = 4\\a_n= a+(n-1)d\\139=7+(n-1)4\\139=7+4n-4\\136+4n\\n=34 th Term\\\\\\HOPE IT HELPS$