which term of an A.P. 8,14,20,............. will be 72 more than its 41 term?
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Answered by
32
refer to the picture....
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Answered by
5
here,
m = 41
x = 72
d = 6
so,
n = m+x÷d
= 41+72/6
= 41+12
= 53.
therefore 31st term of the AP is 72 more than it's 41st term
m = 41
x = 72
d = 6
so,
n = m+x÷d
= 41+72/6
= 41+12
= 53.
therefore 31st term of the AP is 72 more than it's 41st term
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