Question

which term of an ap 11, 8,5,...is minus 136

Answer 1

tn = -136
a= first term =11
d= common difference = 8-11= -3

tn = a + (n-1)d
-136 = 11 + (n-1)(-3)
-136-11 = (n-1)(-3)
-147÷(-3) = (n-1)
49 = n-1
n = 49 + 1
n = 50

therefore, the 50th term of the A.P. is -136

Answer 2

♤Hello!!♤

Given AP 11, 8,5,... - 136

Here First term, a = 11

Common Difference, d = ( a2 - a1 ) = 8 - 11 = - 3

Last term, an = Tn = 136

We know that the nth term of an AP is given by

an = a + ( n - 1 ) * d

=> - 136 = 11 + ( n - 1 ) * ( - 3 )

=> - 136 = 11 - 3n + 3

=> - 136 = 14 - 3n

=> - 136 - 14 = -3n

=> - 150= -3n

=> n = 150 / 3

=> n = 50


Therefore, 50th term of the given AP is - 136

Hope it helps!