Math, asked by shakyaanubhav123456, 10 months ago

Which term of an AP 121,117,113 is first negative term

Answers

Answered by chhayag39
3

Answer:

Step-by-step explanation:

A.P : 121, 117, 113...

a = 121

d =  117- 121= -4

Let an= 0

an = a + (n-1)d

⇒ 0 = 121 + (n-1)(-4)

⇒ 0 = 121 - 4n + 4

⇒4n = 125

⇒ n = 125/4

⇒ n = 31.25

n must be natural number therefore n= 32

Hence, 32nd term is first negative number.

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Answered by udayphrj
2

Answer:

a = 121 and common difference = -4

general term = a + (n-1)d

= 121 + (n-1)*-4 = 121 - 4n + 4 = -4n + 125

let us find the value of n when the expression is 0,

-4n + 125 = 0

n = 125/4 = 31.25

so that means the 32 term is the first negative one.

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