Question

which term of an ap ,121,117,113.....is the first​

Answer 1

Step-by-step explanation:

dont Know sorry...........

Answer 2

Given A.P is 121,117,113...............

a=121 and d=117−121=−4

a

n

=a+(n−1)d

=121+(n−1)(−4)

=121−4n+4

=125−4n

We have find the first term of this A.P.

Therefore a

n

<0

125−4n<0

124<4n

n>

4

125

n>31.25

n=32