which term of an AP: 3,15,27,39,... will be 132 more than its 54th term?
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Answered by
2
Step-by-step explanation:
answer has given in the above attachment.
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Answered by
5
Answer:
65 th term
Step-by-step explanation:
Here a=3, d = 12
An= a+(n-1)d
A54= a+53d
= 3+53*12
=639
we need to calculate 54 th term+132
ie An= 639+132=771
An= a+(n-1)d
771=3+(n-1)12
768= 12(n-1)
768/12=n-1
n-1=64
n=65.
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