Question

which term of an ap 3, 8, 13 is 7 is 478​

Answer 1

given,

last term = an = 478

first term = a = 3

common difference= d= 8-3 and 13-8 = > 5

n = number of terms

an = a +(n-1)d

478= 3+ (n-1) 5

478-3= 5n-5

475+5= 5n

480= 5n

n= 480/5= 96th term

Answer 2

Answer:

n=96

Step-by-step explanation:

a=3

d=5

tn=478

tn=a+(n-1)×d

478=3+(n-1)×5

(n-1)×5=478-3

(n-1)×5=475

(n-1)=475/5

(n-1)=95

n=95+1

n=96

hope you help this

96th term