Question

Which term of an ap 5,15,25 will b 130 more than 31 term?

Answer 1

Answer:

44

Step-by-step explanation:

5,15,25

Let x be the term we want.

a=5; d = 10.

tₙ = a + (n-1)d

t₃₁  = 5 + (31-1)10 = 5 + 300 = 305.

The number which is 130 more than t₃₁ = 305 + 130 = 435.

tₓ = 5 + (x-1)10 = 435

=> (x-1)10 = 435 - 5 = 430

=> x-1 = 430/10 = 43

=> x = 44.

So the term is 44.