Which term of an AP : 78,72,69 .....is 0 ?
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Answer: Yes . It forms the 14 th term of the given AP
Step-by-step explanation:
a= 78
d= 72 - 78 = -6
let the nth term of the given AP be 0
Then, an = 0
==> a+(n-1)d = 0
On putting the values of a and d , we get 78 + ( n -1) (-6) = 0
==> 78 - 6n + 6 = 0
==> 78+ 6 -6n = 0
==> 84- 6n = 0
==> -6n = -84
==> n = -84 / -6
==> n = 14 .
Hence , 14 th term of the given AP is 0 .
Hope it helps
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