which term of an AP 9, 12, 15,..........132
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Step-by-step explanation:
Given: 9,12,15,18,.. are in A.P
where a=9 and d=12−9=3
t
n
=39+t
36
(given)
t
36
=a+35d=9+25×3=9+105=114
t
n
=39+t
36
=39+114=153
⇒a+(n−1)d=153
⇒9+(n−1)×3=153
⇒(n−1)×3=153−9=144
⇒(n−1)=
3
144
=48
⇒n=48+1=49
∴ the 49
th
term is 153 from above
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