which term of an AP is 14 whose first term is -6 and common difference is 1.25
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a = -6
d = 1.25
tn = 14
t = ?
tn = a + (n - 1) d
14 = -6 + (n - 1) 1.25
14 = -6 + 1.25n - 1.25
14 = 1.25n - 7.25
14 + 7.25 = 1.25n
21.25 = 1.25n
n = 21.25/1.25
n = 7
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