Question

Which term of an AP is 2,7,12,17,...... is 137 ?

Answer 1

Answer:

$\huge\red{\boxed{\bold{Answer}}}$

$137 = 2 + (n + 1)5 \\ \\ 137 - 2 = 5n + 5 \\ \\ 135 - 5 = 5n \\ \\ 130 = 5n \\ \\ 26 = n$

Answer 2

$\large \bold{ \underline{ \underline{ \: \sf Answer : \: \: \: }}}$

$\to$ 28th term = 137

$\large \bold{ \underline{ \underline{ \: \sf Explaination : \: \: \: }}}$

Given ,

$\star$ First term ( a) = 2

$\star$ Common difference ( d ) = 5

$\star$ An = 137

We know that ,

$\large \bold{ \fbox{ \fbox{ \blue{An = a + (n - 1)d }}}}$

$\to \sf 137 = 2 + (n - 1)5 \\ \\ \to \sf </p><p>137- 2 = (n - 1)5 \\ \\ \to \sf </p><p> \frac{135}{5} = n - 1 \\ \\ \to \sf </p><p>27 + 1= n \\ \\ \to \sf </p><p>n = 28$

$\therefore$ 28th term of the given AP is 137

_______________ Tera Bhai ❤