Question

Which term of an ap is 2,7,12,17,......is 137

Answer 1

an=a+(n-1)d
137=2+(n-1)5
137-2=n-1)5
135=(n-1)5
135/5=(n-1)
27=n-1
27+1=n
28th term

Answer 2

here first term a=2
and common difference d=7-2=5
an=137
an=a+(n-1)do
137=2+(n-1)5
137-2/5=n-1
135/5=n-1
27+1=n
n=28
there for 28th term of the ap is 137