Question

Which term of an arithmetic progression 2,7,12,17....is 137

Answer 1

Given :- First term ( a ) = 2

Common difference ( d ) = 7-2 = 5

Term ( n ) = ?

an = 137

So, to find term of A.P when digit of that term is given there is a formula

=> an = a + ( n - 1 )d

So, putting values here,

137 = 2 + ( n - 1 )5


137 = 2 + 5n - 5

137 = -3 + 5n

137 + 3 = 5n

140 = 5n

28 = n


So, for the term 28 the A . P. has 137 value.



@Altaf

Answer 2

Answer:

Please mark it as brainly's answer