Math, asked by umarabdullah8868, 5 months ago

Which term of an arithmetic sequence 4,7,10,13,16... is 121? 2 points

Answers

Answered by kudratkomolafehassan
2

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Answered by pravallika2577
1

Answer:

Sequence is

Sequence is 4,7,10,13,16,...

a1=4,a2=7,a3=10,...

a1=4,a2=7,a3=10,...

a1=4,a2=7,a3=10,... If it is Arithmetic sequence,

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3 Since the difference between the successive terms is same and

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3 Since the difference between the successive terms is same andhence

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3 Since the difference between the successive terms is same andhence common difference

a1=4,a2=7,a3=10,... If it is Arithmetic sequence, a2−a1=a3−a2=a4−a3 & so on In the given sum,a2−a1=7−4=3 a3−a2=10−7=3 a4−a3=13−10=3 Since the difference between the successive terms is same andhence common difference d=3

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