Question

which term of AP 1,5,9,13........ is 97​

Answer 1

Step-by-step explanation:

. . . .. . . . .. . .. .. .. . .. .. ... . .

Answer 2

The 25th term of an AP is 97.

Step-by-step explanation:

The given AP are:

1, 5, 9, 13, ........

Here, first term (a) = 1, common difference(d) = 5 - 1 = 4 and $a_{n} =97$

Let nth term is 97.

To find, the value of n = ?

We know that,

The nth term of an AP.

$a_{n} =a+(n-1)d$

⇒ 1 + (n - 1)4 = 97

⇒  (n - 1)4 = 97 - 1 = 96

⇒ n - 1 = $\dfrac{96}{4}=24$

⇒ n = 24 + 1 = 25

Thus, the 25th term of an AP is 97.