which term of ap 10, 15, 20 is 110
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The position of term 110 is 25
Step-by-step explanation:
GIVEN
a = t1 = 10 , t2 = 15 , t3 = 20 , ...
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Difference = t2 - t1 = 15 - 10 = 5
Difference = 5
___________________________
To find the term,
We know that,
an = a + ( n – 1 ) × d
110 = 10 + ( x - 1 ) × 5
110 = 10 + ( 5x - 5 )
110 = 15 + 5x
110 + 15 = 5x
125 = 5x
x = 125 / 5
x = 25
The position of term 110 is 25
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