which term of AP, 121 ,117, 113 is it's first negative term
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difference between 2nd term and 3rd term is,
= (t3 - t2)
= (113 - 117)
= (-4)
so, d= (-4)
here series is in A.P
from this value we get that,
first negetive value will -> 0 + (-4) = -4
now, we have to calculate which term of this series is (-4)
here , l = (-4) , a1 = 121, d = (-4) , n = ?
we know,
I = a1 + (n-1)d
=> (-4) = 121 + (n-1)×(-4)
=> (n-1)×(-4) = -125
=> (n-1) = (125/4)
=> n = 31.25
here n>31.25
so, the term will 32.
ans= 32nd term of this ap series will first negetive term
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