which term of AP: 121‚117‚113‚. ..‚is it's first term?
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Step-by-step explanation:
Given A.P is 121,117,113...............
a=121 and d=117−121=−4
a
n
=a+(n−1)d
=121+(n−1)(−4)
=121−4n+4
=125−4n
We have find the first term of this A.P.
Therefore a
n
<0
125−4n<0
124<4n
n>
4
125
n>31.25
n=32
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