Which term of AP 121, 117,113.. is its first negative term
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Answered by
2
here An =0
a+(n-1)d=0
121+(n-1)4=0
(n-1)=-121
n=-121+1
n=-120
a+(n-1)d=0
121+(n-1)4=0
(n-1)=-121
n=-121+1
n=-120
gauravpandey9652:
Thanks
Answered by
10
Hii friend!!
a= 121
d= -4
find which term is 0
T = a + ( n-1 ) d
0 = 121 + ( n- 1) (-4)
-121 = (n-1) (-4)
-121 = -4n +4
-121 -4 = -4n
-125 = -4n
n = -125/-4
n= 31.25
n = 31
31st term is 0 then next term is negative
so 32nd is the first negative term
hope it will help you
a= 121
d= -4
find which term is 0
T = a + ( n-1 ) d
0 = 121 + ( n- 1) (-4)
-121 = (n-1) (-4)
-121 = -4n +4
-121 -4 = -4n
-125 = -4n
n = -125/-4
n= 31.25
n = 31
31st term is 0 then next term is negative
so 32nd is the first negative term
hope it will help you
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