which term of AP 121..117..113...... is its first negative term ?
pranavrathor:
.j
Answers
Answered by
4
Heya Mate...........................
Here is your answer...............................
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Tn = a + (n - 1)d
= 121 + (n - 1)-4 = 0
= 121/4 +1 = n
= n = 31.25
So, 32th term is its first negative term.
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Thanks............................
Answered by
18
hey here is your answer :----
➡a +( n-1)d < 0
➡121 + ( n -1)-4 < 0
➡121 -4n + 4 <
➡125 - 4n < 0
add 4n on both the sides the we get -
➡125 - 4n + 4n < 4n
-4n and 4n will get canceled
the we get -
➡125 < 4n
divide this eqh by 4
➡125/4< n
➡31.2< n
the value of n is 32 because n is greater than 31.2
hope it helps u....❤❤❤
➡a +( n-1)d < 0
➡121 + ( n -1)-4 < 0
➡121 -4n + 4 <
➡125 - 4n < 0
add 4n on both the sides the we get -
➡125 - 4n + 4n < 4n
-4n and 4n will get canceled
the we get -
➡125 < 4n
divide this eqh by 4
➡125/4< n
➡31.2< n
the value of n is 32 because n is greater than 31.2
hope it helps u....❤❤❤
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