which term of ap:13,19,25,31
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Answer:
the terms of the AP should be an integer, not a fraction
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Step-by-step explanation:
AP : 13, 19, 25, 31, ........
first term, a = 13
common difference, d = a2 – a1
d = 19 – 13
d = 6
an = 1001
an = a + ( n – 1 )×d
1001 = 13 + ( n – 1 ) × 6
1001 = 13 + 6n – 6
1001 – 13 + 6 = 6n
994 = 6n
994 / 6 = n
n = 165.667
Since n is coming out to be fraction therefore 1001 is not a term of the Above AP.
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