Question

Which term of ap 13,25,37,49..... Will be 372 more than its 26th term?

Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{n=57}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

□a=13

□d=a2-a1=12

□an=26th term +372

□n=?

>>first we find 26th term of this A.P

$a26 = a + 25d \\ \: \: \: \: \: \: \: \: = 13 + 25 \times 12 \\ \: \: \: \: \: \: \: \: = 13 + 300 \\ \: \: \: \: \: \: \: \: = 313$

>>So a26=313 and in question it is given that we have to find 372 more than 26th term

>>26th + 372=313+685

□an=685

□n=?

$an = a +( n - 1)d \\ = )685 = 13 + (n \times 1) \times 12 \\ = ) 685 - 13 = (n - 1) \times 12 \\ = ) \frac{672}{12} = n - 1 \\ = )56 + 1 = n \\ = ) n = 57$

$\huge{\boxed{\boxed{\sf{n=57}}}}$

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