Question

which term of ap 27, 39, 51... is 132 more than its 54th term​

Answer 1

Answer:

65th

Step-by-step explanation:

a54 = a+ 53d

a54 = 27+53(12)

a54 = 663

663+132 = 795

an = a + (n-1)d

795 = 27 + 12n - 12

795 - 15 = 12n

n = 780/12

n = 65

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Answer 2

Step-by-step explanation:

In this series 1st term a=27

common difference d=39-27=12

so,54th term =a+(54-1)d

=27+53.12

=27+636

=663

let the n th term is 132+663=795

so,

a+(n-1).d=795

=> 27+(n-1).12=795

=> (n-1).12=795-27=768

=>n-1=768/12=64

=> n=64+1=65

so 65th term is 132 more than its 54 th term