Question

which term of AP 3,11,19z27,.... is 547

Answer 1

hey..!! Here Is Your Solution.
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To find term use Tn = a + (n - 1) × d

ATQ

a = 3 [FIRST TERM OF AP]

d = 8 [DIFFERENCE BETWEEN AP]
____ (T2 - T1 = 11 - 3 = 8)

Tn = 547

NOW, Put value in formula

Tn = a + (n - 1) × d

_547 = 3 + (n - 1) × 8

_547 = 3 + 8n - 8

_547 - 3 = 8n - 8

_544 = 8n - 8

_544 + 8 = 8n

_552 = 8n

n = 536\8

n = 69

Hence, Your Term Is 69..

#RS

HOPE THIS HELPS..☺☺

Answer 2

Hello !!☺️☺️

Here is your answer

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Given ,

first term (a) = 3
common difference (d) =11 -3 = 8
l = 547

Now ,

l = a +( n- 1) d
=>l = 3 + (n- 1)8
=>547 = 3 + 8n - 8
=>547+5 = 8n
=>552/8=n
=>69 = n

Therefore 69 th term is 547.

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Hope it will help you✌️