Question

which term of AP 3,14,25,36..........will be 99 more than its 25th term
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Answer 1

a=3

d=14-3=11

n=25

So, 25th term = a+(n-1)d

                     =3+(25-1)*11

                    =3+24*11 = 3+264 = 267

99 more than 25th term is 267+99  =  366

Let the mth term be 366

Now, we have

a=3

d=11

mth term= a+(m-1)d

366=3+(m-1)11

366-3=(m-1)*11

363/11=m-1

33=m-1

m=34

So 34th term is 99 more than the 25th term of the given AP.

Answer 2

Answer:

34 is your answer

Step-by-step explanation: