Question

Which term of AP 3,15,27,39.....will be 132 more than its 54th term?

Answer 1

Answer:

A = 3

n = 54

d = 12

we know that

a + ( n - 1 ) d

= 3 + ( 54 - 1 ) 12

= 3 + 53 × 12

= 3 + 636

= 639

Now

132 + 639 = 771

771 = 3 + (n - 1) 12

768/12 + 1 = n

64 + 1 = n

n = 65

Therfore 65th term term 132 more than 54th term

Answer 2

SOLUTION

Given,

a= 3

common difference= 12

Then as per given

=) an = 132 + a54

=) a+(n-1)d = 132 +(a+53d)

=) 3+12(n-1) = 132 +(3+53 ×12)

=) 12n -9 = 771

=) 12n = 771 +9 = 780

n= 780/12

=) n= 65

hope it helps ✔️